Which one of the following compounds undergoe | vedclass

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(B) The rate of electrophilic aromatic substitution depends on the electron density of the aromatic ring. Groups with a $+M$ (mesomeric) effect increa

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$1,2,3,4-$Tetrahydroquinoline

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(B) The rate of electrophilic aromatic substitution depends on the electron density of the aromatic ring. Groups with a $+M$ (mesomeric) effect increase the electron density,thereby activating the ring towards electrophilic attack.$A$: Tetralin has only alkyl groups,which are weakly activating.$B$: $1,2,3,4$-Tetrahydroquinoline has an $-NH-$ group directly attached to the benzene ring. The lone pair on the nitrogen atom participates in resonance ($+M$ effect),significantly increasing the electron density of the ring.$C$: $1,2,3,4$-Tetrahydroisoquinoline has the nitrogen atom separated from the ring by a $CH_2$ group,so it does not exert a direct $+M$ effect on the ring.$D$: $3,4$-Dihydroquinolin-$2(1H)$-one has an amide group where the nitrogen lone pair is involved in resonance with the carbonyl group ($-M$ effect),which deactivates the ring.Therefore,$1,2,3,4$-Tetrahydroquinoline $(B)$ undergoes bromination at the fastest rate due to the strong $+M$ effect of the $-NH-$ group.

Which one of the following compounds undergoes bromination of its aromatic ring (electrophilic aromatic substitution) at the fastest rate?

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